By J. B. Sykes, D. ter Haar, L. P. Pitaevskii
Evgenii Mikhailovich Lifshitz may be most sensible identified for his lengthy organization together with his mentor Lev D Landau, with whom he co-wrote the vintage Course of Theoretical Physics, yet he used to be a famous and revered Soviet physicist in his personal correct. Born within the Ukraine to a systematic relatives, his lengthy and special occupation might be remembered for 3 issues - his collaboration with Landau at the across the world acclaimed Course of Theoretical Physics, his paintings as editor of the Journal of Experimental and Theoretical Physics, and his clinical papers. in addition to his paintings with Landau, EMLifshitz collaborated with many famous Soviet scientists corresponding to IMKhalatnikov, IEDyzaloshinskii, VVSudakov, VABelinskii and the editor of this publication, LPPitaevskii. a few of the papers offered during this ebook comprise their contribution. amassed jointly they provide a finished and penetrating perception into the guy and his paintings, truly displaying Lifshitz's contribution to physics and the affects on his paintings.
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Extra resources for Perspectives in Theoretical Physics. The Collected Papers of E. M. Lifshitz
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Therefore the Dispersion of magnetic permeability in ferromagnetic bodies 57 integration over dydz gives the surface ll2 of the layer, and we get the energy for one intermediate region: + 00 %ll2s 2 +00 2 2 2 I ( a 0 ' + j8sin 0)dx = / I 2s ) 8 | J J ch 7^x — oo ^L=- = 2 2 2s ll2Jajt. V — oo There are lx d such regions in the crystal a n d the whole internal energy of the crystal is 2 Ei = 2s ll1l2^/d. (15) We now find the width d of the layers from the condition that the whole energy Ε = Et + Es of the crystal must be a minimum.
S -Hs)dK (19) [it is more convenient to write here the anisotropy energy as — \$s\ instead 2 of 20(s* + s ); both these expressions are evidently equivalent]. We did not write the term H s in the formulae of §1, because the macroscopical field strength inside the crystal was zero when there was n o external field and all s were distributed in a Z F - p l a n e . e. the variation of (19) with s must be equal to zero. This gives J ( a s " +jffs zn + H ) < 5 s d F = 0 (n is a unit vector in the direction of the Z-axis).
In the absence of the field sx = sy = s2 = 0, ft = 0, sx = 0 and if we put (3) into (24) we obtain just equation (5). sx, sy9 s2 in (24) are functions of χ and of the time t. We suppose that both variables enter only in a combination χ — vt9 ν being the velocity of propagation of the whole distribution along the X-axis. Then sx = — svx and the same for sy9 s29 if' now denotes differenti ation by χ — vt. T o solve (24) we put sx = sX9 sy = s s i n ( 0 + ψ)9 s2 = s c o s ( 0 + φ) (25) Dispersion of magnetic permeability in ferromagnetic bodies 61 where 0 is determined from (9) [ a n d satisfies (5) or (6)] where instead of χ must now stand (x — vt).